- #1

- 1

- 0

y=x^3 + 2

I know I need to factor it... I'm just not completely sure how! Thanks!

- Thread starter Calcuconfused
- Start date

- #1

- 1

- 0

y=x^3 + 2

I know I need to factor it... I'm just not completely sure how! Thanks!

- #2

- 172

- 2

[itex]0=x^3+2[/itex]

- #3

Mentallic

Homework Helper

- 3,798

- 94

But regardless, if you need to factor it, you'll end up with a linear factor and a quadratic factor, and since we've already shown one of the roots, the end result will be of the form

[tex]\left(x+\sqrt[3]{2}\right)\left(x^2+ax+\sqrt[3]{4}\right)[/tex]

For some yet to be found constant value a.

- Last Post

- Replies
- 5

- Views
- 52K

- Last Post

- Replies
- 9

- Views
- 30K

- Last Post

- Replies
- 5

- Views
- 4K

- Last Post

- Replies
- 12

- Views
- 6K

- Replies
- 6

- Views
- 53K

- Last Post

- Replies
- 8

- Views
- 4K

- Last Post

- Replies
- 3

- Views
- 3K

- Last Post

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 19K

- Last Post

- Replies
- 4

- Views
- 2K