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Factoring problem

  1. Oct 3, 2005 #1
    How can i factor this nicely, so that i can get a form to inverse-laplace transform it

    [tex]\frac{0.25s}{s^2+0.25s+0.25}[/tex]

    so far i get this in denominator: [tex](s+\frac{1}{8})^2+\frac{15}{64}[/tex]

    after completing the square, but then the last fraction is not a square of anything.... and i need a square there, the way everything else looks...
     
    Last edited: Oct 3, 2005
  2. jcsd
  3. Oct 4, 2005 #2

    CarlB

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    The denominator is already a square. I don't see how you got the other stuff. The answer should be a simple polynomial multiplied by an exponential.

    Carl
     
  4. Oct 4, 2005 #3
    I don't see a square there, if [tex](a+b)^2 = a^2+2ab+b^2[/tex]

    this is a simple algebra thing... i guess i'm not seeing it :frown: could you show please?
     
  5. Oct 4, 2005 #4

    ehild

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    Do not panic. 15/64 is the square of

    [tex]\frac{\sqrt {15}}{8}[/tex]

    :smile:ehild
     
  6. Oct 4, 2005 #5

    CarlB

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    My mistake. I don't see anything wrong with the way you're doing this problem, so far.

    Carl
     
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