#### adjacent

Gold Member

- 1,538

- 63

(I will be learning those names in Gr.11)

Now back to the question

##P_E=mg\sin\gamma x##

##E_K=\frac{1}{2}mv^2+\frac{Mv^2}{4}##

so,

##mg0.6=mg\sin\gamma x+\frac{1}{2}mv^2+\frac{Mv^2}{4}*2##