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## Homework Statement

A chain of mass M and length L is suspended vertically with the lower end touching a scale.

the chain is released and falls onto the scale.

what is the reading of the chain when a length x is fallen?

neglect the size of individual links

## Homework Equations

dp = IMPULSE=F*dt

p=mv

## The Attempt at a Solution

Well this is what I've done so far.

the velocity of the specific part of the chain when it hits the scale is V= sqrt(2gx)

F1= Mgx/L -weight of a X part of the chain.

now the second force is quite a problem.

F2=dp/dt=d(mv)/dt =V(dm/dt)......

what do I do from here??

i need to express dm/dt with the information i got, but cant find a way... =trying to translate it to words: the rate the mass hits the chain or...? I'm kinda stuck.

Any help appreciated!

Thank You.

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