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Falling Flowerpot

  1. Apr 11, 2005 #1
    Falling Flowerpot

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    A 3 kg flowerpot drops from a tall building. The initial speed of the pot is zero, and you may neglect air resistance.


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    a) What is the magnitude of the force acting on the pot while it is in the air 1.5 s after it begins to fall?
    |F| = N *


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    b) After the pot has fallen 26 m, what is its speed?
    |v| = m/s *
    sqrt(2*9.81*26) OK

    HELP: Apply the appropriate formula from one-dimensional kinematics with constant acceleration.


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    c) After the pot has fallen 26 m, it enters a viscous liquid, which brings it to rest over a distance of 1.5 m. Assuming constant deceleration over this distance, what is the magnitude of this deceleration?
    |a| = m/s2 *
    9.81*26/1.5 OK


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    d) What is the force exerted on the liquid by the pot?
    Ft = N

    Need help with part d. Some guidance requested please!!!
     
  2. jcsd
  3. Apr 11, 2005 #2

    Galileo

    User Avatar
    Science Advisor
    Homework Helper

    A constant decceleration means a constant force is applied to it. Use F=ma to find the force the liquid exerts on the pot.
     
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