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How long does it take for the package to reach the ground ?.

The attempt at a solution

I know

U = 12.5ms

A = -9.8ms

V = 0ms

S = 120m

Used t = v-u/a

T = 1.27 Seconds - the time it takes the object to stop ascending

Then used s = ut + .5 at^2 to find distance traveled

S = 7.97 meters

Adding this to the original height of 120m to get 127.97m

So now I have:

U = 0

A = 9.8ms

S = 127.97m

Use v^2 = u^2+2as to calculate the velocity after t

V = 50

Use V - U/A to get time

T = 5.1

Now I added the ascent and decent time to get total time before it hits the grounds

Total Time = 6.37 Seconds

Could someone look over this for me and tell me if I am even close to the correct answer ?.

Any help would be greatly appreciated