Calculating Distance of Falling Rock

In summary, a guy sees a rock falling from a plateau and estimates that the last third of its fall will last for 1.3 seconds without considering air resistance. The relevant equations are the kinematic motion equations, which can be used to determine the position and velocity of an object over time. If the last third refers to time, the problem is simple, but if it refers to distance, more thought is needed to come up with a one variable expression for initial position and velocity.
  • #1
Minkowski
7
0

Homework Statement


- A guy sees a rock falling from a plateau. He estimates the last third (1/3) of the rocks fall to last for 1,3 sec. Air resistance doesn't need to be taken into consideration.

- How far/what distance has the rock fallen?


Homework Equations


None given


The Attempt at a Solution


I was thinking of making a logarithmic equation out of it:

f(x) = b*x^a, f(x) = distance travelled, b = ??, x = 1,3 sec or (1/3) ? and a = 9,82 m/s^2

I am by no means sure about this attempt. Thanks on beforehand.
 
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  • #2
The relevant equations are the kinematic motion equations. They relate the position and velocity and acceleration of an object versus time. What is the velocity of a mass versus time, based on the acceleration of gravity? What is the position of an object versus time, based on its initial velocity and its acceleration? How do these equations help you solve this problem?
 
  • #3
The last third by distance or by time?

If by time, the problems very easy. If by distance, it will take a little thought. From the initial position at the time the person first saw the rock and with an initial velocity, it took 1.3 seconds to complete the fall. You need to figure out how to come up with a one variable expression for the initial position and a one variable expression for the initial velocity (both the same variable).
 

1. How do I calculate the distance of a falling rock?

To calculate the distance of a falling rock, you will need to use the formula d = 1/2 * g * t^2, where d is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time the rock has been falling for. This formula assumes that the rock is falling from rest and is not affected by air resistance.

2. What is the unit of measurement for the distance of a falling rock?

The unit of measurement for the distance of a falling rock will depend on the unit of measurement used for the acceleration due to gravity and time. For example, if g is measured in meters per second squared and t is measured in seconds, then the distance will be measured in meters.

3. Can I use the same formula to calculate the distance of a falling object on other planets?

No, the formula for calculating the distance of a falling object assumes Earth's gravitational acceleration. The acceleration due to gravity varies on different planets, so you will need to use a different formula to calculate the distance of a falling object on other planets.

4. How does air resistance affect the distance of a falling rock?

Air resistance will slow down the falling rock, so it will not reach the distance calculated using the formula d = 1/2 * g * t^2. The actual distance will be less than the calculated distance due to air resistance. This effect is more significant for objects with a larger surface area, such as a feather.

5. Is it possible to calculate the distance of a falling rock without knowing the time it has been falling for?

No, the formula for calculating the distance of a falling rock requires the time the rock has been falling for. Without this information, it is not possible to calculate the distance. However, if you know the initial and final velocities of the rock, you can use the formula d = (v0 + vf)/2 * t, where v0 is the initial velocity, vf is the final velocity, and t is the time interval.

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