(adsbygoogle = window.adsbygoogle || []).push({}); Problem:

A rigid assembly is made of a light weight rod 2 m long and a heavy gold ball which is attached at the middle of the rod. The rigid assembly initially rests with one end on the ground in a vertical position. If released what speed does the top of the rod have when it strikes the ground?

Equations:

[tex]Rotational \ Inertia \ for \ a \ thin \ rod \ about \ central \ axis; \ \ I = \frac{1}{12} M L^{2}[/tex]

[tex]Rotational \ Inertia \ for \ a \ thin \ rod \ about \ non-central \ axis; \ \ I = \frac{1}{12} M L^{2} + M R(from \ center)^{2}[/tex]

[tex]Rotational \ Inertia \ for \ a \ sphere; \ \ I = \frac{2}{5} M r^{2}[/tex]

My Work:

Any help where to start? I am lost. I know that the final answer is 8.85 m/s.

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# Homework Help: Falling Rod, Rotation?

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