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OP warned about not using the homework template
Can anyone help me on this problem from this video starting from 8:03 , I've been working on it for a week ,and I couldn't find a solution.
Correct. What would happen if he didn'tAhmedemad22 said:I think he used his timer to apply force to the ruler
##Mv^2/l=mg\cos x-n\sin x\ ##: in ##\ mv^2\over 2\ ## I see some energy. In ##\ mgl\cos x\over 2\ ## also. But the other one ? Perhaps it's good to set up a list of known/unknown variables and a few more equations -- all of these important constituents of the template !Ahmedemad22 said:Describing normal force from the floor.
Do you have a ruler and a reasonably smooth surface nearby ?Ahmedemad22 said:Maybe, ruler wouldn't slide , correct?
What is ##nl\sin x\over 2 ## ?Ahmedemad22 said:can you explain further?
and did you observeAhmedemad22 said:Yes , I have made that experiment twice.
as correct or as proven wrong ?Ahmedemad22 said:Maybe, ruler wouldn't slide , correct?
gravity is one componentAhmedemad22 said:what makes the centripetal force to the center of the mass
How do you now ?Ahmedemad22 said:It wouldn't slide if he didn't put the timer.
'it' being 'blocked the foot of the ruler from sliding to the left' (while the ruler is falling to the right) ?Ahmedemad22 said:And it slided when i did it
NoAhmedemad22 said:It wouldn't slide if he didn't put the timer. And it slided when i did it
Yes. So you reproduced Walters result.Ahmedemad22 said:I pushed the ruler a bit and it started to fall then it's gone away from the block i put behind it , and slided until it lied at the surface
Yes, Walter said it was more complicated. And no, there does not seem to be a worked out solution within google range. We have to think for ourselvesAhmedemad22 said:This problem is more trickier for me , I even tried to search about it but i didn't find anything helpful
In my case the bottom end of the ruler (that is falling to the right) slides to the left, already when theta is about 30 degrees.Ahmedemad22 said:It slided also but only when it lied at the ground
It certainly can. That's why the block is needed -- for the horizontal componentAhmedemad22 said:can a force which is applied from the pivot point make a radial acceleration?
That's the vertical component and the normal force works outwards, but: yesAhmedemad22 said:i.e the normal force from the surface that touches the pivot point
No. The ruler is not just translating but also rotating. So more complicated than the girl on the igloo: there is a rotational energy term too.Ahmedemad22 said:So Mv^{2}/l=mg cos(x) ?
Ahmedemad22 said:And does normal force from the block does torque?I don't understand why we need opposite torque