Faraday law of induction

  • Thread starter chukie
  • Start date
  • #1
80
0
A circular coil, with radius of 10 cm, and 25 turns, rotates in a constant magnetic field of
strength 2.4 T, with the axis of rotation perpendicular to the direction of the magnetic
field.
If the coil rotates at a frequency of 50 Hz, what is the induced peak voltage?

Okay so I know the equation to use is:
emf=-Ndelta flux/delta t

I know all the variables in the equation except for time. I was wondering how you calculate the time. Is it just 1/50Hz?
 

Answers and Replies

  • #2
dynamicsolo
Homework Helper
1,648
4
What is happening during that 1/50 of a second? The coil is being spun around an axis perpendicular to the external magnetic field. So what is going on with the flux through the coil? (The magnetic field strength is not changing at all!)
 
  • #3
80
0
What is happening during that 1/50 of a second? The coil is being spun around an axis perpendicular to the external magnetic field. So what is going on with the flux through the coil? (The magnetic field strength is not changing at all!)
So is the change in time just 1/50=0.02s? The number seems a bit small to me.
 
  • #4
Redbelly98
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
12,121
159
Have you had calculus and used derivatives yet?

You would start by figuring out an expression for the flux as a function of time, then take the derivative.
 
  • #5
Redbelly98
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
12,121
159
So is the change in time just 1/50=0.02s? The number seems a bit small to me.
No. After 0.02s (or 1 period), the flux will be exactly what it was at 0.00s. This is because the flux is a periodic function of time, with period 0.02s.
 

Related Threads on Faraday law of induction

  • Last Post
Replies
11
Views
3K
  • Last Post
Replies
4
Views
882
  • Last Post
Replies
2
Views
4K
Replies
5
Views
5K
Replies
2
Views
2K
  • Last Post
Replies
5
Views
3K
Replies
3
Views
4K
Replies
5
Views
2K
Replies
1
Views
7K
Replies
0
Views
2K
Top