1. Feb 21, 2005

### triplezero24

Ok, I need a lot of help on this one. A single conducting loop of wire has an area of 7.4*10^-2 m^2 and a resistance of 110 ohms. Perpendicular to the plane of the loop is a magnetic field of strength 0.18 T. At what rate (in T/s) must this field change if the induced current in the loop is to be 0.22 A?

So far all I can figure out is that Phi=BA. And I don't think that has anything to do with this problem. :grumpy:

Thanks for any and all help.

2. Feb 21, 2005

### StatusX

Well, how do you relate the change in flux to the induced EMF? And once you have that, just use ohm's law to get the current.

3. Feb 21, 2005

### stunner5000pt

you should know these formulae from your text

flux $$\Phi = \int B dA Cos \theta$$
and induced emf $$E = \frac{d \Phi}{dt}$$
and also the induced Emf is just live a voltage really so E = IR.

now try and rearrange these equatios to solve