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## Homework Statement

A 21.8 cm diameter coil consists of 18 turns of circular copper wire 1.70 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.15E-3 T/s. Determine the current in the loop.

## Homework Equations

V=IR

V=B/T * A * N

permitivity of copper= 1.72e-8

R=p * L / A'

## The Attempt at a Solution

V = 8.15e-3 * (.218/2)^2 * pi * 18 turns = 0.005475 V

L = N * pi * coil diameter = 18 * pi * .218 = 12.32 m

A'= pi * (.0017/2)^2 = 2.269e-6 m^2

R = 1.72e-8 * (12.32 m/2.269e-6 m^2) = 0.0934 ohms

I = V/R = 0.005475 V / 0.0934 ohms = 0.0586 A

But thats wrong... where'd I go wrong?