A 21.8 cm diameter coil consists of 18 turns of circular copper wire 1.70 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.15E-3 T/s. Determine the current in the loop.
V=B/T * A * N
permitivity of copper= 1.72e-8
R=p * L / A'
The Attempt at a Solution
V = 8.15e-3 * (.218/2)^2 * pi * 18 turns = 0.005475 V
L = N * pi * coil diameter = 18 * pi * .218 = 12.32 m
A'= pi * (.0017/2)^2 = 2.269e-6 m^2
R = 1.72e-8 * (12.32 m/2.269e-6 m^2) = 0.0934 ohms
I = V/R = 0.005475 V / 0.0934 ohms = 0.0586 A
But thats wrong... where'd I go wrong?