Calculating Voltage Amplitude with Faraday's Law

In summary, Farraday's Law states that the voltage of an object is equal to the negative product of the number of turns and the rate of change of magnetic flux. However, determining the amplitude of the induced electric charge can be complex as it depends on the nature and movement of the particles inside the object. If the particles are in an AC current, the voltage and magnetic flux will vary periodically, allowing for the determination of the amplitude by finding the point where the derivative of the voltage is equal to 0. However, this may not be applicable to the current as the inductor may oppose its change.
  • #1
RoscoeSlash
7
0
Farraday's Law states V= -N.flux/time , if this calculates voltage how does one determine amplitude?
 
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  • #2
Amplitude of what?
 
  • #3
amplitude of the induced electric charge
jtbell said:
Amplitude of what?
 
  • #4
I assume you are talking about a loop of wire. It presumably has a certain resistance. The voltage produces a current in the wire. The current is related to the amount of charge that flows by...? (what's the definition of current?)
 
  • #5
The thing is, that the function that describes the magnetic field of the object is not necessarily a wave.
The vector field function, from which you obtain the voltage of the object, varies according to the speed of the particles moving inside of it, depending on the nature of this movement, the function will take an specific "form" and this is not necessarily a periodic one, and as such, there is no thing as an "amplitude" on all cases, thought of curse, if the source of this particles is an AC current, in which case, the energy, and in consequence, the speed of the particles would change with time forming a periodic function, the object (inductor) would experiment too, a periodic variation on both it's voltage and magnetic flux; in this case, you can "cut-out" an oscillation of the wave function, get the derivative (with respect of time of course) of the voltage and see on which point inside the interval of the oscillation this derivative is equal to 0, the value for "V" on that "t" value would be the amplitude (you can do something similar too for the other functions of the system, like magnetic flux, except, I believe, for the current, because the inductor seems to oppose the change of current).
 
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1. What is Faraday's Law and how does it relate to calculating voltage amplitude?

Faraday's Law is a fundamental principle in electromagnetism that states that a changing magnetic field will induce an electric field. This electric field can then be used to calculate the voltage amplitude at a specific point.

2. How is Faraday's Law applied to calculate voltage amplitude?

To calculate voltage amplitude using Faraday's Law, you need to know the rate of change of the magnetic field, the distance from the source of the magnetic field, and the angle between the direction of the magnetic field and the direction of the induced electric field.

3. Can Faraday's Law be used to calculate voltage amplitude in any situation?

No, Faraday's Law can only be used to calculate voltage amplitude in situations where there is a changing magnetic field. If the magnetic field is not changing, there will be no induced electric field and therefore no voltage amplitude.

4. What are some real-world applications of calculating voltage amplitude with Faraday's Law?

Faraday's Law is used in a variety of technologies, such as generators, transformers, and electric motors. It is also used in scientific research to measure the strength and direction of magnetic fields.

5. Are there any limitations to using Faraday's Law to calculate voltage amplitude?

One limitation is that Faraday's Law assumes a perfect conductor, which may not always be the case in real-world situations. Additionally, it is only accurate for calculating voltage amplitude at a specific point, and may not account for variations in the electric field at other points.

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