1. The problem statement, all variables and given/known data Find the linear and angular accelerations given that FA is the applied force. v is the current linear velocity and w is the current angular velocity. r is the radius of the stick. h is length of the stick. d is angle from the vertical axis. 2. Relevant equations a = dv/dt; linear acceleration u = dw/dt; angular acceleration Icenter = m h2/12; moment of inertia of stick 3. The attempt at a solution Sum of horizontal forces: m ax = -FA ax = -FA/m Sum of vertical forces: may = -mg + FN = 0 Sum of torque T = I u = 0.5 h FN sin(d) - 0.5 h FA cos(d) u = 0.5 h ( mg sin(d) - FA cos(d) ) / ( m h2/12 ) u = ( 6 / m h )( mg sin(d) - FA cos(d) ) Is this correct? Shouldn't the vertical acceleration be non-zero? Because if w and u are non-zero, and the finger maintains at the same height, then the center of mass of the stick must be moving. What is wrong with the above? - Thanks And thank you for replying to my other thread. There are so many threads I thought I shouldn't bump the one that was solved.