Here are the tabulated t = time (sec), v = velocity (m/s) = g(t), and d = displacement (m)=4.9(t)^2 for an object if dropped (free fall) from rest position. When t=0, v=0, d=0 When t=1, v=9.8, d=4.9 When t=2, v=19.6, d= 19.6 When t=3, v=29.4, d= 44.1 When t= 4, v=39.2, d=78.4 When t=5, v=49, d=122.5 When t= 3600, v= 35280, d=63504000 Question: 1- At the end of first second; velocity of a free fall object is 9.8 m/s while its displacement is 4.9m. Why its displacement less than 9.8 m? 2- Similarly, displacement w.r.t velocity is increases after 2nd second (time) – not identical. Because 9.8 m/s means an object cover a distance of 9.8 m in one second. 3- Is it wrong to say that there exiting an initial acceleration (POTENTIAL) of 9.8 m/s/s if an object dropped from rest (free fall) – just like a mass rest on ground?