• Support PF! Buy your school textbooks, materials and every day products Here!

Fermi energy

  • Thread starter glebovg
  • Start date
  • #1
164
1

Homework Statement



Calculate the Fermi energy for magnesium, assuming two free electrons per atom.

Homework Equations



[itex]{E_F} = \frac{{{\hbar ^2}}}{{2m}}{(3{\pi ^2}\rho )^{2/3}}[/itex], where [itex]\rho = q\frac{N}{V}[/itex] and q is the number of free electrons.

The Attempt at a Solution



q = 2, so [itex]\rho = 2\frac{N}{V} = 2\left( {\frac{{{\text{atoms}}}}{{{\text{mol}}}}} \right)\left( {\frac{{{\text{mol}}}}{{\text{g}}}} \right)\left( {\frac{{\text{g}}}{{{\text{volume}}}}} \right) = 2\frac{{{N_A}}}{M}\frac{m}{V}[/itex].

i.e. [itex]2\left( {\frac{{{\text{the Avogadro constant in mo}}{{\text{l}}^{ - 1}}}}{{{\text{molar mass in g/mol}}}}} \right)\left( {{\text{density in g/c}}{{\text{m}}^3}} \right)[/itex].

etc.

Is this the right approach? Is the formula for [itex]{E_F}[/itex] correct?
 

Answers and Replies

Related Threads on Fermi energy

  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
6
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
3
Views
700
  • Last Post
Replies
0
Views
3K
  • Last Post
Replies
1
Views
6K
  • Last Post
Replies
3
Views
630
  • Last Post
Replies
7
Views
10K
Replies
2
Views
2K
Top