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Fermi level of n-type semiconductor Nd>Na>0
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[QUOTE="girlinphysics, post: 5261263, member: 522248"] [h2]Homework Statement [/h2] This isn't actually a homework question, but in my semiconductors textbook, the following equation has been given: [tex]E_f = E_g - k_BTln(\frac{n_0}{N_d - N_a})[/tex] This is for the limiting case Nd>Na>0. I got a little confused as to where that equation has come from. [h2]Homework Equations[/h2] [tex]N_d - N_a[/tex] (Where Nd = donor level and Na = acceptor level) Also: [tex]E_F = E_g - E_d[/tex] [h2]The Attempt at a Solution[/h2] I think this means the fermi level is at donor level so I can write: [tex]n = n_0e^{\beta(E_f - E_g)} = n_0e^{-\beta E_d}[/tex] where beta = 1/kT Is this how they got to that equation? Just by rearranging for Ef? [/QUOTE]
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Fermi level of n-type semiconductor Nd>Na>0
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