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Ferris Wheel physics

  1. Sep 24, 2011 #1
    1. The problem statement, all variables and given/known data

    I have to find the mass m of a person riding a ferris wheel sitting on a bath scale.
    Given data:
    R=16 m
    Scale reading on top of ferris wheel = 510 N
    Scale reading at bottom of the ferris wheel= 666 N

    2. Relevant equations

    [itex]F=ma[/itex]

    For uniform circular motion we have:
    [itex]a_{rad}=\frac{v^2}{R}[/itex]

    3. The attempt at a solution

    I know that three forces are acting on the person on both top and bottom of the wheel:
    gravity Fg, the normal force Fn and the centripetal acceleration.

    The reason that i'm stuck is that I can't understand this:

    What is the resulting force? the centripetal acceleration?
    I have read that the normal force in this situation is bigger at the bottom that on the top? Why is that?

    If I answer these questions I can use Newtons 2nd law.

    Thanks.
     
  2. jcsd
  3. Sep 24, 2011 #2

    PeterO

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    Homework Helper

    Acceleration is not a force!!

    You should be referring to, and calculating, centripetal Force mv2/R

    The force you are calling the Normal Force, is correctly named the Normal Reaction Force.

    Being a Reaction Force it is as big as it needs to be, that is why it is bigger at the bottom of the loop than at the top.

    The net force [the centripetal force] at the bottom is directed up. You have to add a large upward Reaction force to the weight force to get an answer that is directed up.
    The net force [the centripetal force] at the top is directed down. You have to add a smaller upward Reaction force to the weight force to get an answer that is directed down.

    and note: there are only two forces acting on the passenger. The weight force, due to gravity, and the Normal Reaction Force - due to the passenger contacting the seat.

    Those two combine to give the net force in many situations - In this case it is the centripetal force.
     
  4. Sep 24, 2011 #3
  5. Sep 24, 2011 #4
    Thanks for the clarifications. The normal reaction force is directed upwards at both top and bottom, right? So Fn is less than gravity on the top and bigger than gravity at the bottom?

    What exactly makes the normal reaction force change magnitude?
     
  6. Sep 24, 2011 #5

    PeterO

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    Homework Helper

    The reaction force is exactly that - a reaction.
    Place you hand on a table - the table pushes back with a certain force.
    Now push a little harder on the table - the table pushes back a little harder.
    Now push on the table as hard as you can - the table pushes back as hard as you could.

    place a 500kg mass on the table - and either the table will push back with sufficient force to support it, or the table will collapse.

    Friction is a reaction force too. the uR calculation [coefficient of Friction x Reaction force] tells you the maximum possible friction force [analogous to the strength of the table above].

    Suppose uR worked out to be 100N

    if you push a mass on that surface with a force of 5N, friction will be 5N, and nothing moves.
    Push with 20N, friction is 20N
    Push with 80N, friction is 80N
    Push with 100N, friction is 100N
    Push with 120N and the mass moves.
     
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