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What force [magnitude and direction (measured inward from the vertical)] does the seat exert on a 43.0 kg rider when the rider is halfway between top and bottom, going up?

Ok, the magnitude is easy...

Fnet = m(centripetal acceleration^2 + acceleration due to gravity^2)^1/2 = 422.77 N

What I can't figure out to save my life is the direction "measured inward from the vertical"..

My thinking is to basically make a triangle (similarly to the method used to find Fnet) with 33.95 N being the opposite side (pushing in), and the adjacent side being 421.4 N (pushing up). This gives 0.08 degrees in from vertical, which is incorrect.

What am I doing wrong here?

Thanks!