A Ferris wheel that rotates three times each minute and has a diameter of 16.0 m What force [magnitude and direction (measured inward from the vertical)] does the seat exert on a 43.0 kg rider when the rider is halfway between top and bottom, going up? Ok, the magnitude is easy... Fnet = m(centripetal acceleration^2 + acceleration due to gravity^2)^1/2 = 422.77 N What I can't figure out to save my life is the direction "measured inward from the vertical".. My thinking is to basically make a triangle (similarly to the method used to find Fnet) with 33.95 N being the opposite side (pushing in), and the adjacent side being 421.4 N (pushing up). This gives 0.08 degrees in from vertical, which is incorrect. What am I doing wrong here? Thanks!