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Ferris Wheel trig question

  1. Jul 17, 2010 #1
    I have this question in my trig/pre cal class and I have no idea how to approach it what so ever.

    In 1893, George Ferris engineered the Ferris Wheel. It was 250 feet in diameter. If the wheel makes 1 revolution every 50 seconds, then

    h(t) = 125sin (pi/25t - pi/2) + 125

    represents the height (h), in feet, of a seat on the wheel as a function of time (t), where t is measured in seconds. The ride begins when t = 0.

    a.) During the first 50 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 125 feet above the ground?

    Thank you!!
  2. jcsd
  3. Jul 17, 2010 #2
    Sometimes a diagram of the problem helps visualise the solution.
    Draw the ferris wheel, add a line 125 feet off the ground, and find out what angle of rotation will bring the passenger to that height.
    I have to stop now, and leave you with something to do!
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