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Ferris wheel

  • Thread starter ffrpg
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  • #1
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The problems reads, A carnival Ferris wheel has a 14.2m radius and completes one revolution about its horizontal axis in 10.1s. Consider the time interval from the instant when a passenger is at the lowest point of the uniform circular motion to a clock reading 5.05 seconds later. What was the magnitude of the passenger's average acceleration during this time interval?


Do I use the formula (they're suppose to be vectors) a=(-rwcoswt)i+(-rwsinwt)j? I really don't have any direction towards solving this problem. Any hints would be wonderful.
 

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  • #2
Tom Mattson
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Originally posted by ffrpg
Do I use the formula (they're suppose to be vectors) a=(-rwcoswt)i+(-rwsinwt)j? I really don't have any direction towards solving this problem. Any hints would be wonderful.
That should be:

a=-rω2cos(ωt)i-rω2sin(ωt)j

You forgot to square the angular velocity, but other than that it's OK.
 

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