Few stupid questions about polar curves and stuff.... Okay, here's the first dumb question. I have to find the tangent line where r=2-3sin(T) at the polar point (2,pi). To find the slope, you just take dy/dx, and I come up with 2/3. I know that part is right. T=theta (I know it's spelled wrong) But how do I turn this into an equation for the tangent line? Do I just use y=mx+b? That seems too simple for this, and I would think she would want it in polar coordinates, not cartesian. Secondly, what (cos2(T))^2. is it 2cos(2T) or 2 cos(4T) or what? I know we learned this like 2 years ago, but I just can't remember anymore. Thanks guys!!!