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Feynman diagram

  • Thread starter hob
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hob
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1. Homework Statement

What observation of the process: (anti muon neutrino) + (electron) -> (anti muon neutrino) + (electron) constitutes unambiguous evidence for weak neutral currents,

whereas the observation of (anti electron neutrino) + (electron) -> (anti electron neutrino) + (electron)

3. The Attempt at a Solution


The solution is the first one:

{www}.scribbleproductions.co.uk/stuff/fine1.jpg

Since the second reaction can undergo via W+ as well as Z0:

{www}.scribbleproductions.co.uk/stuff/fine2.jpg


My question is in the Feynman diagrams, why could you not have this for example:

An electron decaying to a muon neutrino ?

{www}.scribbleproductions.co.uk/stuff/fine3.jpg

Apparently the weak interaction also violates charge conservation, but I have never seen a possible reaction with a Feynman diagram that is violated at the vertices's.

Many thanks for any help :)
 

Answers and Replies

nrqed
Science Advisor
Homework Helper
Gold Member
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1. Homework Statement

What observation of the process: (anti muon neutrino) + (electron) -> (anti muon neutrino) + (electron) constitutes unambiguous evidence for weak neutral currents,

whereas the observation of (anti electron neutrino) + (electron) -> (anti electron neutrino) + (electron)

3. The Attempt at a Solution


The solution is the first one:

{www}.scribbleproductions.co.uk/stuff/fine1.jpg

Since the second reaction can undergo via W+ as well as Z0:

{www}.scribbleproductions.co.uk/stuff/fine2.jpg


My question is in the Feynman diagrams, why could you not have this for example:

An electron decaying to a muon neutrino ?

{www}.scribbleproductions.co.uk/stuff/fine3.jpg

Apparently the weak interaction also violates charge conservation, but I have never seen a possible reaction with a Feynman diagram that is violated at the vertices's.

Many thanks for any help :)
The weak interaction does NOT violate charge conservation! So your third diagram is impossible. Charge is always conserved
 
hob
6
0
The weak interaction does NOT violate charge conservation! So your third diagram is impossible. Charge is always conserved
Thanks for that, I was a bit uneasy to see charge violation.

Does weak violate anything to do with charge? I remember seeing something about charge violation that only the weak does not strong or e.m

Regards,
 

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