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lets say we have the scattering process [itex]e^- + \nu_{\mu} \rightarrow \mu^- + \nu_e[/itex] via the weak interaction. This would then be mediated by a W-Boson, right? Now my question ist: Which one?

The Feynman-Diagramm should then look like the one on the right:

http://accessscience.com/loadBinary.aspx?aID=9704&filename=450700FG0010.gif" [Broken]

(in the line on top, one has to exchange [itex]e \rightarrow \mu[/itex]

I know that this diagramm actually represents two processes (which could be drawn as slightly "skewed" diagramms):

1) The electron emits a [itex]W^-[/itex] and thereby "changes" into an [itex]\nu_e[/itex]. This [itex]W^-[/itex] is then absorbed by the [itex]\nu_{\mu}[/itex] which therefore "changes into a [itex]\mu^-[/itex]

2) The [itex]\nu_{\mu}[/itex] emits a [itex]W^+[/itex] and changes into a [itex]\mu^-[/itex]. The [itex]W^-[/itex] is then absorbed by the [itex]e^-[/itex] and changes into a [itex]\nu_e[/itex]

So if I draw the Feynman-diagramm as in the link, is it ok to write [itex]W^+[/itex]? Because wouldn't that mean that the diagramm only represents option 2)? Or am I wrong to assume that [itex]W^+[/itex] and [itex]W^-[/itex] both have to do with the process and only one of the processes 1) and 2) is the "right" one?

I have a big exam in particle physics soon. If the professor asks me to draw the Feynman-diagramm for this process I simply wouldn't know what to write ( [itex]W^+[/itex], [itex]W^-[/itex] or maybe forget about the charge (just write [itex]W[/itex]) and hope the professor doesn't ask which of the W's it is?).

I know that my question is not very precise, so here is the short version:

What belongs in the diagramm?

a) W+

b) W-

c) simply W, because W+ and W- both have to do with the process

d) other

Thank you very much,

QuantumCosmo

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# Feynman-Diagramm: W+ or W-?

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