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## Summary:

- Can anyone explain this in layman's words?

I'm new to QED, so I want to have a general grasp of what's going on. I just want to understand it conceptually. Can anyone explain it in a way so a layman can understand?

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- Thread starter DeltaForce
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- #1

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## Summary:

- Can anyone explain this in layman's words?

I'm new to QED, so I want to have a general grasp of what's going on. I just want to understand it conceptually. Can anyone explain it in a way so a layman can understand?

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DarMM

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The Feynman diagrams are pictures/graphs you can draw with two types of lines, photon and electron with one rule for joining lines: photon lines can only be joined with two electron lines. We call joinings verticies.

Each line and vertex is connected with certain mathematical functions and the number of loops tells you how many integrations you have to perform.

The more verticies there are the less important the effect of that graph, and usually by about five or so verticies the effect is so small we often ignore it.

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(*) In the sense that if the energies are too high, then QED is no longer sufficient to describe phenomena, but the Glashaw-Salam-Weinberg electro-weak theory is the proper one.

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So from a high-school perspective: small magnets and electrons presented as points of no dimension and mass 9.10^-31 Kg and charge -10^-19 C are replaced by abstract (fictive if you want) "fields" of the same type of field with which the electric and magnetic fields generated by these classical objects are replaced.

QED is a quantum field theory. Stress on Quantum, and stress on "field", but this field is not something you can directly measure.

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DarMM

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I read parts of the QED lecture. It said that light can take an infinitely different route, but some routes are more likely for light to take. My question is that how does that idea relate to the Feynman diagrams (where 2 electrons deflect off each other because of a photon)

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Yes, (if I remember correctly) the probability of a route is the square of the sum of the amplitudes of all possible routesAs an extension question,

I read parts of the QED lecture. It said that light can take an infinitely different route, but some routes are more likely for light to take.

It is also a sum of amplitudes but the lines on Feyman diagrams are not routes. The diagram shows all the ways in which given initial states can become (proposed ) output states. To calculate the probability of this one must sum the amplitudes for all the ways over all space. It is very technical as this paper ( 'Feynman diagrams for beginners') shows. The diagram that you think is an electron anihilating with a being deflected is not that. It is probably an electron anihilating with a positron.My question is that how does that idea relate to the Feynman diagrams (where 2 electrons deflect off each other because of a photon)

https://arxiv.org/pdf/1602.04182.pdf

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When we talk about light "taking different routes", we are basically talking about one Feynman diagram: the one that has just one photon line coming in and one photon line going out, with nothing happening in between. In other words, this one Feynman diagram represents an infinite set of possibilities: all of the possible paths that a photon could take between two fixed points in spacetime. Integrating over all those paths gives the probability amplitude that QED, or more precisely the pure photon part of QED (i.e., no electrons or interactions, just photon propagation), predicts for a photon that is emitted from the first point in spacetime to be detected at the second point.It said that light can take an infinitely different route, but some routes are more likely for light to take. My question is that how does that idea relate to the Feynman diagrams (where 2 electrons deflect off each other because of a photon)

The full theory of QED does the same sort of thing, but with more possible diagrams. For example, if we include electrons and the possibility of electrons interacting with photons, then even the simple photon propagator--i.e., the amplitude for a photon emitted at one spacetime point to be detected at another spacetime point--has to include more than just the one simple diagram described above, because now things can happen to the photon in between the emission and detection events. For example, the photon could turn into an electron-positron pair, which could then annihilate each other and turn back into a photon. The Feynman diagram for this would have one photon line going in, ending at a loop of one electron line, and another photon line beginning on the other side of the electron loop and going out. (The technical name for this diagram is "vacuum polarization".) This diagram also represents an infinite number of possibilities, since the photon could go anywhere in spacetime before turning into the electron-positron pair and then back into a photon again. And there are further possibilities when we start considering that other photon lines could start and end on the electron loop (staying completely internal to the diagram), and those other photon lines could then spawn other electron loops, etc., etc., etc.

In practice, because each photon-electron vertex in the diagram gets a factor of ##\sqrt{\alpha}## (where ##\alpha## is the fine structure constant), which is a fairly small number, the amplitudes for these different possibilities get rapidly smaller as the diagrams get more complicated. So we can calculate reasonable predictions by taking into account just a few of the simplest diagrams. (For example, the Lamb shift can be reasonably estimated just with the vacuum polarization diagram I described above.)

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Thank you! That cleared up a lot of things.

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What's the mechanism behind how an electron emits (or absorbs) a photon? How does that work?

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Nobody knows. We don't even know if the question is meaningful. Electrons and photons aren't little machines. They're just electrons and photons. There might be no answer to the question of how they do what they do, other than "that's what they do". At some point, the search for a "mechanism", which basically means explaining something in terms of something else, has to stop; there has to be something fundamental, that just does what it does without being explainable in terms of something else.What's the mechanism behind how an electron emits (or absorbs) a photon? How does that work?

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We don't measure electrons emitting single photons. The "electron emits a photon" process is a virtual process; it's part of the theoretical model shown in Feynman diagrams. It's not something we directly measure.Do electrons just go off an emit photons randomly? Or only when a circumstance happens? Is there a pattern to it?

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So how did Feynman arrive at "electron emits a virtual photon?" And it carries momentum which causes electrons to recoil and deflect off each other.We don't measure electrons emitting single photons. The "electron emits a photon" process is a virtual process; it's part of the theoretical model shown in Feynman diagrams. It's not something we directly measure.

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From the math of QED, which contains terms that, when translated into Feynman diagrams, can be interpreted that way. But the interpretation is not important; the predictions are. QED would make the same predictions if you didn't even try to interpret Feynman diagrams at all, but just did the integrals they told you to do and got numbers out. All the talk about electrons emitting and absorbing photons is just a way many physicists like to describe the diagrams in ordinary language to help them think about the calculations.how did Feynman arrive at "electron emits a virtual photon?"

We don't observe this either. We observe electrons appearing to repel each other via an "electromagnetic force", but we don't observe individual photons traveling between them and pushing on them. The photons are virtual photons. And the virtual photons appearing in the Feynman diagrams for things like the static Coulomb repulsion between electrons aren't even on shell, meaning they don't obey the relativistic energy-momentum relation for photons (another way to put it is that they don't travel at the speed of light).it carries momentum which causes electrons to recoil and deflect off each other.

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Coming back to the basic scenario of two electrons shot at each other and bounce off. That is what the most basic Feynman diagram represents I think.

In classical physics, the electrons are surrounded by an electric field; so they they push each other apart. In quantum physics, those electric field supposedly are made of individual discrete photons (i think).

Does that information have to do with these "virtual photons" we're talking about?

If so, how?

I also read the book

If any of that information relevant to the electron situation I mentioned above?

Sorry again, I'm still a novice to these quantum physics stuff. I don't really know what I'm talking about. I'm trying my best to piece together information to form a big picture.

I'm very thankful that you're taking time to answer my (probably) dumb questions.

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There are an infinite number of Feynman diagrams for this case. The simplest one has two electron lines coming in, two electron lines going out, and a single internal photon line between them. But there are more complicated diagrams that have more internal lines. (Actually, even that's not the simplest possible diagram--see below.)Coming back to the basic scenario of two electrons shot at each other and bounce off. That is what the most basic Feynman diagram represents I think.

Note that even the simplest diagram is not correctly described as "two electrons shot at each other and bounce off". The electrons don't interact with each other directly. They interact by exchanging a photon (a virtual photon).

Made of virtual photons, which we never directly measure.In quantum physics, those electric field supposedly are made of individual discrete photons (i think).

Also, this description is based on the description of QED in terms of Feynman diagrams, which actually are only one possible way of viewing QED. This way, which is more general than just QED (it can be applied to any quantum field theory) is called "perturbation theory", because each of the Feynman diagrams containing internal lines can be viewed as a perturbation, or correction, to the most basic diagram that just has the external lines with nothing happening in between.

For example, remember that I said in an earlier post that "light taking different routes" refers to the simplest possible Feynman diagram for a single photon, where it just goes in and comes out and nothing happens in between. All of the more complicated diagrams with one photon line going in and one photon line coming out are perturbations to this.

For the case of two electrons--i.e., two electron lines going in and two electron lines coming out--the simplest possible Feynman diagram is actually one with just two electron lines--two going in and two coming out--with nothing happening in between. All of the other diagrams, including the one with just a single internal photon line between the two electrons, are perturbations to that. So basically QED on this perturbation theory view is just adding up all the possible perturbations to nothing happening at all!

This is actually another way to view the pure photon part of QED; the "path of least time" described in that chapter is the same as the "path of greatest amplitude" when you calculate the integral over all possible paths for the simplest one-photon Feynman diagram.In the 2nd chapter, it talks about light and how it is most likely to take the path of least time required to travel

Not really, because, as I said above, when we are talking about electrons repelling each other, the photons they are exchanging are virtual photons; whereas when we are talking about light propagation and the various phenomena described in QED chapter 2, we are talking about real photons that we actually observe (more precisely, we observe the light propagation phenomena being described).If any of that information relevant to the electron situation I mentioned above?

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You're welcome! (Your questions aren't dumb; all of us started out not knowing about this stuff.)I'm very thankful that you're taking time to answer my (probably) dumb questions.

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