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Feynman rules

  1. Sep 22, 2014 #1
    Hi
    I want to drive the amplitude by feynman rules?
    a spin 0
    medium.png
    particle with mass m0 that couples to spin 0 particles with masses m1, . . ., mN by a point-coupling ig and a target that interacts with only one of the constituents.
    the transverse momentum transfer dependence proportional to \exp{-\beta \vec{q}^2_\perp}

    the answer is below but I don't know how to reach this answer.

    [tex]{\cal M}=\frac{2 i g p_N.q}{(p_0-\sum_{j=1}^{N}p_j)^2 - m_N^2} \exp (-\beta \vec{q}^2_\perp /2 )[/tex]

    I just know in the form below to write
    [tex]{\cal M}=\bar{u}(p_1)...\bar{u}(p_N) i g u(p_0)\frac{\gamma ^\mu (p_0-\sum_{j=1}^{N}p_j)_\mu + m_N}{(p_0-\sum_{j=1}^{N}p_j)^2 - m_N^2} X u(q)[/tex]
     
    Last edited by a moderator: Sep 22, 2014
  2. jcsd
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