Field of a Polarized Object

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If it equals zero, then E must be zero outside the sphere.In summary, the given problem involves a sphere with a radial polarization of P = krn\hat{r}, where k and n are constants and n \geq 0. The volume and surface charge densities of bound charge are found to be σb = krn and ρb = -(n+2)krn-1, respectively. The expressions for E inside and outside the sphere are Einside = -krn\hat{r}/ε0 and Eoutside = 0, respectively. The potential V is also calculated inside and outside the sphere. A sketch of the results is also provided.
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KeyToMyFire
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Homework Statement



A sphere of radius a has a radial polarization P = krn[itex]\hat{r}[/itex] where k and n are constants and n [itex]\geq[/itex] 0.

a.) Find the volume and surface charge densities of bound charge.

b.) Find E outside and inside the sphere. Verify that you results for E satisfy the appropiate boundary conditions.

c.) Find V (potential) outside and inside the sphere.

d.) Sketch the results.

Homework Equations



σb = P [itex]\cdot[/itex] [itex]\hat{n}[/itex]

ρb = -[itex]\nabla[/itex] [itex]\cdot[/itex] P

The Attempt at a Solution



I got

σb = krn

and

ρb = -(n+2)krn-1

which I'm pretty sure is right, but then for E I get

Einside = -krn[itex]\hat{r}[/itex]0

which seems okay and then

Eoutside = 0

which doesn't seem right.Can anybody tell if this is right or not? And if not how to do it?
 
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I think everything is correct, except you need to specify a specific value of r in your expression for σb.

To see if it's reasonable that E = 0 outside the sphere, calculate the net charge of the sphere due to both the bound volume charge density and the bound surface charge density.
 
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1. What is a polarized object?

A polarized object is an object that has a non-uniform distribution of electric charges, causing it to have a distinct positive and negative end. This polarization can occur naturally, such as in crystals, or can be induced by an external electric field.

2. How does the electric field of a polarized object differ from a non-polarized object?

The electric field of a polarized object is different from a non-polarized object because the polarized object has a dipole moment, resulting in a non-uniform electric field. In a non-polarized object, the electric field is uniform and the net charge is evenly distributed.

3. How is the field of a polarized object calculated?

The field of a polarized object can be calculated using Coulomb's law, which states that the electric field at a point is equal to the force between two charges divided by the square of the distance between them. In the case of a polarized object, the electric field is the vector sum of the fields from each individual dipole moment within the object.

4. What is the relationship between the strength of the electric field and the degree of polarization?

The strength of the electric field is directly proportional to the degree of polarization. This means that the more polarized an object is, the stronger its electric field will be. This relationship is due to the fact that a higher degree of polarization means a larger dipole moment, resulting in a stronger electric field.

5. How does the electric field of a polarized object affect its surroundings?

The electric field of a polarized object can affect its surroundings in several ways. One way is through the induction of charges in nearby objects, resulting in a redistribution of charges. Another way is through the attraction or repulsion of other polarized objects, depending on the orientation of their dipole moments. Additionally, the electric field can influence the behavior of charged particles, such as electrons, within its vicinity.

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