- #1

xma123

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Really haven't a clue how to go about this, it's the last question on the paper and nothing before it is anything near as complex as this.

Any help much appreciated

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- Thread starter xma123
- Start date

- #1

xma123

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- 0

Really haven't a clue how to go about this, it's the last question on the paper and nothing before it is anything near as complex as this.

Any help much appreciated

- #2

Doc Al

Mentor

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- #3

voko

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Imagine the top charge is also absent. What would the field be due to the four charges?

- #4

xma123

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The 4 in the middle cancel, giving a field of either positive or negative of the single field charge above. So would the answer be option 3?

- #5

voko

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What is the direction of j? Of the field?

- #6

xma123

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What is the direction of j? Of the field?

The picture is all the info given on this

- #7

Doc Al

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Good. That's the magnitude of the field, so be sure to count the direction.So due to each charge the field is E=kq/r^{2}

Yes, the 4 in the middle cancel. But I don't know what you mean by "either positive or negative". Which is it? What's the direction of the field from the top charge?The 4 in the middle cancel, giving a field of either positive or negative of the single field charge above.

- #8

voko

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- #9

xma123

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By positive or negative I was referring to the difference betweent options 3 and 4.

- #10

voko

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the top charge would act in the upwards of y

Why is that?

- #11

xma123

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Why is that?

Oh damn, they're positive charges, so the field acts downwards away from the top charge.

This would give a "negative" field in the y direction and so option 4 is correct?

- #12

voko

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they're positive charges, so the field acts downwards away from the top charge

Correct!

- #13

xma123

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Correct!

Thanks very much for your patience, much appreciated

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