Consider a uniformly charged sphere of radius R and total charge Q. The electrical field E(out) outside the sphere (r>R) is simply that of a point charge Q. Gauss's law was used to find E(in) inside the sphere(r<R) is radially ouwards with the field strength(adsbygoogle = window.adsbygoogle || []).push({});

Ein = (1/4*pi*epsilon0)*(Q/R^3)*r

A) Graph E vs r for 0<r<3R

b) The electric potential Vout outside the sphere is that of a point charge Q. Find an expression for the electric potential Vin at position r inside the sphere.

c)What is the ration Vcentre/Vsurface

d) Graph V vs r for 0<r<3R

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# Homework Help: Field to Potential Conversion

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