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Fields and Potential

  1. Nov 19, 2013 #1
    1. The problem statement, all variables and given/known data

    The electric field on the x-axis due to a point charge fixed at the origin is given by E=(a/x2)i, where a = 6.00 kVm and x is not equal to zero.
    a) Find the magnitude and sign of the point charge
    b) Find the potential difference between the points on the x-axis at x=1 m and x=2 m.
    c) What is the potential energy of a proton at both positions?


    2. Relevant equations

    E=kq/^2
    Vb-Va=-∫Edl

    3. The attempt at a solution

    a) I've got the magnitude but im unsure how to find the charge?
    b) using Vb-Va=-∫Edl, but if im honest, im not 100% sure how to use the equation
    c) havent attempted yet
     
  2. jcsd
  3. Nov 19, 2013 #2
    What is the magnitude of charge you have calculated ?

    For finding the sign of charge ,does the Electric field points towards or away from the point charge placed at the origin ?
     
    Last edited: Nov 19, 2013
  4. Nov 19, 2013 #3
    for a) i equalled a/x^2 and kq/x^2 cancelling to give q=a/k. subbing in values i got 6.67x10^-7 C. How would i know which direction the field is pointing?
     
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