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Final angular speed of disk

  1. Apr 11, 2007 #1
    A flat uniform circular disk (radius = 4.69 m, mass = 280 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a frictionless axis perpendicular to the center of the disk. A 55.0-kg person, standing 1.59 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 1.70 m/s relative to the ground. Find the resulting angular speed (in rad/s) of the disk.

    i know that i have to use :

    0=I(person)w(final person) + I(disk)w(final disk)

    and i know I=mr^2

    but i just don't know how to rearrange everything....correctly..
  2. jcsd
  3. Apr 11, 2007 #2
    post this in the homework section
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