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Find the 40th term of the arithmetic knowing the general term a(n) = a(n-1) + 4 and first term a1 = 13.

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- #1

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Find the 40th term of the arithmetic knowing the general term a(n) = a(n-1) + 4 and first term a1 = 13.

- #2

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What class is this?

(we just started that stuff in BC calculus :tongue2: )

(we just started that stuff in BC calculus :tongue2: )

- #3

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College Math 2.

- #4

Astronuc

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If I am reading this right, isn't a(40) = a(1) + 39 * 4 = 13 +156 = 169?

or more generally, a(n) = a(1) + (n-1)*4

or more generally, a(n) = a(1) + (n-1)*4

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That looks like it might be right. My friend said it was 159, but I think you've got it right.

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edit: nvm, being stupid. :yuck:

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vsage

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A vector v has initial point P = (5, 2) and terminal point Q = (-3, -2). Find its position vector and write v in the form ai + bj.

- #9

Astronuc

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or what vector added to the vector to P would give you the one to Q.

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So would the final answer be 2i + 0j, which would be technically just 2i?

- #11

Astronuc

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5i + xi = -3i

2j + yj = -2j

2j + yj = -2j

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So is xi = -8 and xj = -4?

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Astronuc

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Yes, in the form ai + bj, a=-8, b=-4 or v = -8i -4j.

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What are the coordinates for graphing the equation y = sin 6 Ø by plotting points?

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Any help would be tremendously appreciated.

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I wish I was taking your math class. That sounds like grade 11 math.Poweranimals said:

Find the 40th term of the arithmetic knowing the general term a(n) = a(n-1) + 4 and first term a1 = 13.

Sigh.

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Poweranimals said:

What are the coordinates for graphing the equation y = sin 6 Ø by plotting points?

wouldn't you just take the points for the graph y=sinx and increase the 'x' coordinates by a factor of 6?

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Yeah, you're right. But I'm stiff baffled as to what coordinates are y=sinx.cAm said:wouldn't you just take the points for the graph y=sinx and increase the 'x' coordinates by a factor of 6?

- #19

vsage

If I understand the equation correctly, the equation would be shrunk horizontally by a factor of 6. Either the question wants a graph of [tex]sin(6\Theta)[/tex] or maybe the critical points where the graph crosses the x axis. Don't you just love semantics?cAm said:wouldn't you just take the points for the graph y=sinx and increase the 'x' coordinates by a factor of 6?

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I hate math. :p