Final speed ?

  • Thread starter bboycs
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  • #1
bboycs
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final speed ??

A 5 kg vase is lifted vertically from rest to a distance of 10 m with a constant upward applied force of 60.0 N. Calculate

iii) the final speed of the vase

F=ma
60=5(a)
a=12

v^2 = U^2+2as
v^2=0+2(12)(10)
V^2 = 240
v= 15.49m/s

is the step correct~??

thanks for reply~
 
Last edited:

Answers and Replies

  • #2
method_man
69
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  • #3
bboycs
7
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is that have to include mg??
 
  • #4
method_man
69
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is that have to include mg??
Yes. You have three forces acting on a vase: F, mg & ma.
 
  • #5
bboycs
7
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Yes. You have three forces acting on a vase: F, mg & ma.

then can you show me the step to get the final speed??
 

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