1. The problem statement, all variables and given/known data On a pleasant fall day(temperature of 21.0 C) a lump of clay (with mass of .885kg) is thrown against the wall with speed of 38.0 m/s. the clay deforms as it sticks to the wall, noiselessly. assuming no heat escapes into the air, what will the final temp of the clay be.(clay starts at same temp as the air) Cclay=2555j/kgK 2. Relevant equations Q=cm(change in Temp)T Q=change in KE KE=1/2mv(squared) 1/2mv(squared)=cm times the (change in temp) 3. The attempt at a solution 1/2(.885kg)(38.0 m/s)squared=(2555j/kgK)(.885kg)*Change in temp of clay. (.4425kg)(1444)=(2261.175)(change in temp of clay) 638.97=(2261.175)(change in temp of clay) .283 C=change in temp of clay final temp=.283+21.0 final temp=21.28 i did it three times but the answer doesnt seem right to me. if it loses no energy shouldnt all of it be transformed into heat. some when please tell me what im doing wrong.