- #1
xpatelsxownage
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Homework Statement
On a pleasant fall day(temperature of 21.0 C) a lump of clay (with mass of .885kg) is thrown against the wall with speed of 38.0 m/s. the clay deforms as it sticks to the wall, noiselessly. assuming no heat escapes into the air, what will the final temp of the clay be.(clay starts at same temp as the air) Cclay=2555j/kgK
Homework Equations
Q=cm(change in Temp)T
Q=change in KE
KE=1/2mv(squared)
1/2mv(squared)=cm times the (change in temp)
The Attempt at a Solution
1/2(.885kg)(38.0 m/s)squared=(2555j/kgK)(.885kg)*Change in temp of clay.
(.4425kg)(1444)=(2261.175)(change in temp of clay)
638.97=(2261.175)(change in temp of clay)
.283 C=change in temp of clay
final temp=.283+21.0
final temp=21.28
i did it three times but the answer doesn't seem right to me. if it loses no energy shouldn't all of it be transformed into heat.
some when please tell me what I am doing wrong.