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Final temperature after pouring soda into glass with ice....
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[QUOTE="NY152, post: 5625457, member: 608091"] [h2]Homework Statement [/h2] Soda from a ms=12 oz can at temperature Ts=13 degrees C is poured in its entirety into a glass containing a mass mI=0.16kg amount of ice at temperature TI=-19.5 degrees C. Assume that ice and water have the following specfic heats c1=2090 J/(kg*C) and cs= 4186 J/(kg*C), and latent heat of fusion of ice is Lf=334 kj/kg. a) In degrees celsius, what is the final temperature Tfinal of the mixture? b) Write an expression for how much of the ice m[SUB]melted [/SUB] has melted? c) In kilograms, how much of the ice m[SUB]melted[/SUB] has melted? [h2]Homework Equations[/h2] Q= m*c*deltaT [h2]The Attempt at a Solution[/h2] So I think you start by converting the 12 oz can to kg to get the mass at that particular temperature. Then would you set two separate Q equations equal to one another to solve for Tf? So Q= ms*cs*(Tf-13) and Q= mI*cI*(Tf-(-19.5)) and set these equal to each other, but then how does the latent heat of fusion of ice play into the calculation? [/QUOTE]
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Final temperature after pouring soda into glass with ice....
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