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Final velocity help

  • #1
What will the final velocity of 5.0 g bullet starting from rest if a net force of 45 N is applied over a distance of 0.80 m ?


2.


3. i tried to solve it but i don't know of my anwer is correct
F=ma, F/m=a
45/.005 kg
a=9000m/s^-2
From this formula ( d=1/2at^2) we can say that
Time= 2d/a and then take under root
2×0.80/9000 (under root or square root)
=0.013 sec
initial velocity (u) =0
a=v-u/t
at=v-u
9000×0.013=v-0
117+0=v
answer is 117m/s^-1
 
Last edited by a moderator:

Answers and Replies

  • #3
CWatters
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You get 120m/s if you don't round down to 0.013 seconds.
 
  • #4
You get 120m/s if you don't round down to 0.013 seconds.
I don't understand what you mean by this. Please tell what does it mean because i am only in 8 grade
 
  • #5
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I don't understand what you mean by this. Please tell what does it mean because i am only in 8 grade
What CWatters means is that 0,013 s is not the exact value of the time. If you use the exact value, which is t = (2*0,8/9000)^(1/2), you will get a slightly different, more correct answer. I would recommend googleing "significat numbers". :)
 
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  • #6
What CWatters means is that 0,013 s is not the exact value of the time. If you use the exact value, which is t = (2*0,8/9000)^(1/2), you will get a slightly different, more correct answer. I would recommend googleing "significat numbers". :)
Thank you very much for your help. I also had the same answer but the problem was that i shortened 0.0133333333333 to 0.013 thats why my answer was 117 and not 120.
 

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