final velocity...need help!! 1. The problem statement, all variables and given/known data An object is to be thrown through a window 3.25 m high a distance 8 m away. It is launched at an angle 75 degree above the horizontal. The initial launch speed at the specified angle which will allow the projectile to pass through the window is 13.3 m/s. What is the final speed of the object (that is, the speed at which it flies through the window)? Y= height Yo= initial height Voy= initial speed Vf= final velocity g= gravity t= time 2. Relevant equations 1)Y= Yo+Voy*t-(1/2)gt^2 2)Vf= Vo+at 3. The attempt at a solution By using the y= yo+Voy*t-(1/2)gt^2 formula, = 3.25+ (13.3sin75)t-(1/2)(-9.81)t^2 I found the time t=2.85 s But then the answer i got by using the formula Vf= Vo+at = 13.3+ (-9.81)(2.85) = -14.7 m/s IS wrong!!What is my mistake??