A boy fires a "BB" gun at an angle of 28o above the horizontal. The "BB" strikes a target that is a vertical distance of 1.6 meters above and 12.8 meters to the right of the muzzle (exit point) of the gun. Assuming the bullet has a negative vertical velocity when it strikes the target, calculate the bullet's velocity when it leaves the gun.(adsbygoogle = window.adsbygoogle || []).push({});

i tried everything that i could think of, using trig to figure out

Vx=Vy/tan(28) and therefore Vy/tan(28)=12.8

anything that i would plug into the y=VoT + 1/2(a)(Tsqrd) i would get a negative square root

Thanks in Advance

Anshu

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# Homework Help: Final Velocity with barely anything AP Phys help

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