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Problem: A hockey puck is given an initial velocity of 40.0 m/s

along the ice. Find the speed of the puck 1.00 s later if

the coefficient of kinetic friction (U) between puck and ice is

0.600. (HINT: The result is independent of the mass of

the puck.)

My solution:

1. sum of forces in y direction = N - W = 0

2. sum of forces in x direction = p - f = (a)

p - (U)(N) = a

p - (0.600)(g) = a

p - 5.88 = a

( I need to know what "a" is in order to solve for final velocity but I am doing something wrong... please help)

PS. is my body diagram correct?

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# Final Velocity

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