- #1
Spectre32
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Ok I have a surface withthe eqn of x^2 + 2y^2 +3z^2 = 12. The question tells us that there is a perpendicular plane tangent to the the line is as follows:
x = 1 + 2t
y = 3 + 8t
z = 2 - 6t
x = 1 + 2t
y = 3 + 8t
z = 2 - 6t
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