First of all, a "force" cannot be pulled! I presume you mean that an object is being pulled, at 25 degrees by a force with horizontal component Fx. 25 degrees to what? The x-axis? Assuming, since Fx= Fcos(25) where F is the magnitude of the force, F= Fx/cos(25) so Fy, the vertical component, is
Fy= Fsin(25)= Fx(sin(25)/cos(25))= Fx tan(25). In order to find the acceleration, you will also need to know the mass of the object.