Problem is: 2 cos 3x - 1 = 0 Here's how I've done it so far: 2 cos 3x = 1 cos 3x = 1/2 Now I'm stuck. Where do I go from here? Do I divide the 3 out making it cos x = 1/6? I know how to find all the real solutions once I find what cos x is. I'm just having trouble figure out exactly how to get cos x in that type of problem. Any help is grealy appreciated.