- #1

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**Problem is:**

2 cos 3x - 1 = 0

**Here's how I've done it so far:**

2 cos 3x = 1

cos 3x = 1/2

Now I'm stuck. Where do I go from here? Do I divide the 3 out making it cos x = 1/6? I know how to find all the real solutions once I find what cos x is. I'm just having trouble figure out exactly how to get cos x in that type of problem.

Any help is grealy appreciated.

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