Show how you arrived at this answer.aliciaw0 said:i dont understand why
(-m_2*g)/(((-m_2)/2)-m_1) isnt right
That's correct. (Be careful with signs.)because the a of mass#2 is (-a_1)/2 right?
OK.aliciaw0 said:x m_1: T=m_1*a_1
Two problems here:y m_2: T-m_2*g=m_2*a_2
If m_1 moves to the right, then m_2 moves down: this means that if you call a_1 positive, then by your sign convention for m_2, its acceleration should be negative a_2.a_2= a_1/2