# Find Angle of Incline

• cugirl
That's a separate problem. So, in summary, a block with a mass of 4.5 kg slides down a frictionless incline a distance of 3m and then slides across a horizontal floor with friction (coefficient of friction is 0.52) at a speed of 7m/s at the bottom of the incline. The problem is to determine the angle of the incline, assuming constant acceleration.

## Homework Statement

A block (starting from rest) with mass m = 4.5 kg slides down a frictionless incline a distance of d = 3m and then slides across a horizontal floor with friction (the coefficient of friction is Fk = 0.52). The speed of the block at the bottom of the incline is v1 = 7m/s. What is the angle of the incline? (Assume the acceleration was constant.)

## Homework Equations

v initial = 0
mgsin(mu) - ƒk = ma

## The Attempt at a Solution

I am wondering if I am approaching this correctly.
mgsin(theta) - ƒk = ma

Last edited:
cugirl said:

## Homework Statement

A block (starting from rest) with mass m = 4.5 kg slides down a frictionless incline a distance of d = 3m and then slides across a horizontal floor with friction (the coefficient of friction is Fk = 0.52). The speed of the block at the bottom of the incline is v1 = 7m/s. What is the angle of the incline? (Assume the acceleration was constant.)

## Homework Equations

v initial = 0
mgsin(mu) - ƒk = ma

## The Attempt at a Solution

I am wondering if I am approaching this correctly.
mgsin(mu) - ƒk = ma

I hope you mean mgsinθ.

I would be concerned if you were trying to plug in μ, usually used for the coefficient of friction, as the angle.

sorry -- that's what I meant. All the greek letters -- uggh.

As to the problem, the equation you have doesn't address the basic acceleration down the incline, if your statement of the problem is correct in saying the incline is frictionless.