- #1

New user has been reminded that showing an attempt at the solution is mandatory in homework threads at the PF.

## Homework Statement

A 75 kg man stands on a 8meter 25kg ladder at 6 meters above the bottom when it just starts to slip. Mu(s) is.3. What is the angle of the ladder?

ladder mass=25kg

ladder length=8m

man mass= 75kg

radius of man slipping = 6m

Mu=.3

angle= ?

## Homework Equations

F= Mu x Normal force

Torque=rFsintheta

X: P=F(s)=Mu(s) x Normal Force = Mu(s) (Weight of ladder + Weight of man) = Mu(s) (Ladder mass x g + mass man x g)

Y: Normal force = weight of ladder + weight of man

(radius of p)(P)(sin angle)= (radius of ladder)(weight of ladder)(cos theta)+(height of man slipping)(weight of man)(cos theta)

## The Attempt at a Solution

not sure where to start... [/B]