1. The problem statement, all variables and given/known data A small puck of mass 36 g and radius 25 cm slides along an air table with a speed of 1.9 m/s. It makes a glazing collision with a larger puck of radius 59 cm and mass 85 g (ini- tially at rest) such that their rims just touch. The pucks stick together and spin around af- ter the collision. Note: The pucks are disks which have a moments of inertia equal to 1/2mR^2. What is the angular momentum of the sys- tem relative to the center-of-mass after the collision? Answer in units of kgm2/s. 2. Relevant equations L=Iw w=V/r Torque=I*alpha L=RxP 3. The attempt at a solution To be honest I have no idea. I tried several obviously ill-fated attempts. I have found the center of mass, and I know that it has to do with crossing the initial linear momentum with the new radius... I think... Any help would be greatly appreciated.