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vu10758
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The problem is problem 6 at
http://viewmorepics.myspace.com/index.cfm?fuseaction=viewImage&friendID=128765607&imageID=1460003525
A long thin rod of mass M and length L with two balls of mass M1 (same mass for both) attached is allowed to rotate about the horizontal axis shown. The bar is initially stationary. It is then hig with a piece of putty of mass M2 and speed v which sticks to one of the M1's.
a) Find the angular velocity of the system after the collision. The correct answer should be 6M2*v/ (6M1L + 3M2L + ML)
b) What angle will the system rotate through before coming to a stop? Assume that it must be between 180 and 270 degrees.
For part a,
Am I suppose to use the conservation of angular momentum.
IW = I_f*W_f
(1/12)ML^2 *w= (1/12)(M1+M2)*L^2*W_f
I am stuck though since I don't know how to account for v.
For part b,
The answer is 180 + arcsin(V^2/gL)
I don't know how to get to v^2/gL.
http://viewmorepics.myspace.com/index.cfm?fuseaction=viewImage&friendID=128765607&imageID=1460003525
A long thin rod of mass M and length L with two balls of mass M1 (same mass for both) attached is allowed to rotate about the horizontal axis shown. The bar is initially stationary. It is then hig with a piece of putty of mass M2 and speed v which sticks to one of the M1's.
a) Find the angular velocity of the system after the collision. The correct answer should be 6M2*v/ (6M1L + 3M2L + ML)
b) What angle will the system rotate through before coming to a stop? Assume that it must be between 180 and 270 degrees.
For part a,
Am I suppose to use the conservation of angular momentum.
IW = I_f*W_f
(1/12)ML^2 *w= (1/12)(M1+M2)*L^2*W_f
I am stuck though since I don't know how to account for v.
For part b,
The answer is 180 + arcsin(V^2/gL)
I don't know how to get to v^2/gL.