"The Cartesian equation of the plane containing the line x=3t , y =1+t , z=2-t and passing through the point (-1,2,1) is?"
n \bullet (r - r_0 ) = 0 \\
< n_1 ,n_2 ,n_3 > \bullet < x - x_0 ,y - y_0 ,z - z_0 > = 0 \\
The Attempt at a Solution
direction vector is < 3 , 1, -1>
< - 1,2,1 > \bullet < x - 3,y - 1,z + 1 > = 0 \\
- x + 2y + z = 2 \\
But this doesn't appear to be right. Could someone help me out here please. I'm at a lost on how to do this. Thanks