A uniform log of length 2.33 m has a mass of 94.9 kg and is floating in water. Standing on this log is a 72.7-kg man, located 18.9 cm from one end. On the other end is his daughter (m = 26.1 kg), standing 1.15 m from the end. Find center of mass 2. m1r1+m2r2/(m1+m2)=R 3. I used (1.15)*26.1+72.7*0.189/(26.1+72.7+94.9) the answer is not right...Need some help. Thank you!