1. The problem statement, all variables and given/known data Find the curvature of the spiral of Archimedes r = 2θ 2. Relevant equations ||v x a || / ||v||^3 3. The attempt at a solution I tried to convert the polar equation into parametric and got x = 2θsinθ y = 2θsinθ z = 0 I think took the derivative of x y and z and got x' = -2θsinθ + 2cosθ y' = 2θcosθ + 2sinθ z' = 0 I then put them into vectors and used the cross product to get v x a and got the magnitude to be 4θ^2. I found ||v||^3 to be 8θ^3 so I got || v x a || / ||v^3|| = (1/2θ) .